Question

Give the hybridizations of the carbons, from left to right, in CH3CH=CHCl.

A) sp3, sp2, sp3
B) sp2, sp3, sp2
C) sp3, sp, sp2
D) sp, sp3, sp3

Answer 1

The hybridizations of the carbons, from left to right, in CH3CH=CHCl are sp³, sp, sp, and sp².

Step-by-step explanation:

Carbon atoms 1 and 4 have four single bonds and are thus tetrahedral with sp³ hybridization. Carbon atoms 2 and 3 are involved in the triple bond, so they have linear geometries and would be classified as sp hybrids.