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Which set of conditions would accomplish the following transformation in high yield?

A) High temperature, low pressure
B) Low temperature, low pressure
C) High temperature, high pressure
D) Low temperature, high pressure

User JeffN
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1 Answer

6 votes

Final answer:

Based on the information provided, the set of conditions that would accomplish the transformation in high yield is Low temperature, high pressure.

Therefore, option D) Low temperature, high pressure.

Step-by-step explanation:

The transformation in question seems to be related to a chemical reaction where the conditions for maximizing yield are being sought. In general, for an exothermic reaction, lower temperatures favor the production of products therefore maximizing the yield due to Le Chatelier's Principle. When dealing with a reaction involving gases, higher pressures are beneficial for reactions where the number of moles of gaseous products is less than the number of moles of gaseous reactants, as this increases the concentration of reactants per unit volume and drives the equilibrium towards the products.

However, if the reaction is endothermic, higher temperatures are preferred, as this provides the necessary energy for the reaction to proceed. According to the ideal gas law, real gases behave most like an ideal gas under conditions of high temperature and low pressure, where the intermolecular forces become negligible, and the volume of the gas particles is far less significant than the volume in which they are contained.

Given the information from different contexts, if we are discussing a reaction like the Haber process, which is exothermic, the appropriate condition would be low temperature and high pressure (Answer D). However, if we are discussing an endothermic reaction, a high temperature and high pressure condition (Answer C) would be most suitable to maximize yield. As the exact transformation is not provided in the question, it's crucial to know whether the reaction is exothermic or endothermic to select the right set of conditions.

Therefore, option D) Low temperature, high pressure.

User HRKoder
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