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F(x)=4x^2-50x 126 the given equation defines the function f. for what vlue of x does f(x) reach its minimum

a,x=6
b.x=5
c.x=-5
d.None of the above

1 Answer

4 votes

Final answer:

To find the value of x where the function f(x) reaches its minimum, use the vertex formula x = -b/2a. Plugging in the values from the given quadratic function, we find that x = 6.25. Therefore, the correct answer is d. None of the above.

Step-by-step explanation:

To find the value of x where the function f(x) reaches its minimum, we can use the vertex formula which states that the x-value of the minimum or maximum point of a quadratic function in the form f(x) = ax^2 + bx + c is given by x = -b/2a.

In this case, the function f(x) = 4x^2 - 50x + 126 is in the form f(x) = ax^2 + bx + c, where a = 4, b = -50, and c = 126.

Plugging these values into the formula, we get x = -(-50)/(2*4) = 50/8 = 6.25.

Therefore, none of the given options (a, b, or c) correspond to the value of x where f(x) reaches its minimum.

The correct answer is d. None of the above.

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