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The function p is defined by p(n)=7n^3. what is the valye of n when p(n) is equal to 56

User Putna
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Final answer:

The value of n is 2 when the function p(n) = 7n^3 is equal to 56. This is found by isolating n and taking the cube root of 8.

Step-by-step explanation:

The question asks us to find the value of n when the function p(n) = 7n^3 is equal to 56. To solve this, we set the function equal to 56 and solve for n:

7n^3 = 56

To isolate n^3 on one side, we divide both sides of the equation by 7:

n^3 = 56 / 7

n^3 = 8

Next, to solve for n, we need to take the cube root of both sides:

n = ∛8

n = 2

Therefore, the value of n when p(n) is equal to 56 is 2.

User Dhagz
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