Question

64x ^2 −16ax+4bx−ab=0. in the given equation, a and b are positive constants. the sum of the solutions to the given equation is k4a b , where k is a constant. what is the value of k ?

Answer 1

The sum of the solutions to the given quadratic equation is 1/16

Step-by-step explanation:

The given equation is a quadratic equation of the form ax² + bx + c = 0, where a = 64, b = -16a + 4b, and c = -ab. We can find the sum of the solutions, denoted as S, using the following formula:

S = -b/a

Substituting the given values, we have:

S = -(-16a + 4b)/64 = (16a - 4b)/64 = 4a - b/16 = k*4ab

To find the value of k, we can compare the expressions: 4a - b/16 and k*4ab. From this, we can conclude that k = 1/16.