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What is the simplified form of √ ( (128x⁵y⁶)/(2x⁷y⁵) ) ?

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Answer:

√ ( (128x⁵y⁶)/(2x⁷y⁵) ) = \(\frac{8\sqrt{y}} x\right\)

User IronSean
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Final answer:

To simplify √ ( (128x⁵y⁶)/(2x⁷y⁵) ), divide numerically and algebraically to get √(64y/x²), which simplifies to 8y/x.

Step-by-step explanation:

To find the simplified form of √ ( (128x⁵y⁶)/(2x⁷y⁵) ), we first need to simplify the expression under the square root by dividing the numerators and the denominators. We start by simplifying the numeric part 128/2 which equals to 64. Next, we simplify the variables by subtracting the exponents of like bases since we are dividing. For x⁵/x⁷, we get x⁵-⁷ which simplifies to x⁻² or 1/x². For y⁶/y⁵, the simplification is y⁶-⁵ which equals to y.

Now that we have the simplified form of the expression under the square root, we have √(64y/x²). Taking the square root of 64 gives us 8, and the square root of y would just be y since it is already a perfect square. But, for x², the square root is x since x² equals x multiplied by itself.

The final simplified form after taking the square root is therefore 8y/x.

User Eddym
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