168k views
3 votes
What is the simplified form of √ ( (128x⁵y⁶)/(2x⁷y⁵) ) ?

2 Answers

2 votes

Answer:

√ ( (128x⁵y⁶)/(2x⁷y⁵) ) = \(\frac{8\sqrt{y}} x\right\)

User IronSean
by
7.1k points
0 votes

Final answer:

To simplify √ ( (128x⁵y⁶)/(2x⁷y⁵) ), divide numerically and algebraically to get √(64y/x²), which simplifies to 8y/x.

Step-by-step explanation:

To find the simplified form of √ ( (128x⁵y⁶)/(2x⁷y⁵) ), we first need to simplify the expression under the square root by dividing the numerators and the denominators. We start by simplifying the numeric part 128/2 which equals to 64. Next, we simplify the variables by subtracting the exponents of like bases since we are dividing. For x⁵/x⁷, we get x⁵-⁷ which simplifies to x⁻² or 1/x². For y⁶/y⁵, the simplification is y⁶-⁵ which equals to y.

Now that we have the simplified form of the expression under the square root, we have √(64y/x²). Taking the square root of 64 gives us 8, and the square root of y would just be y since it is already a perfect square. But, for x², the square root is x since x² equals x multiplied by itself.

The final simplified form after taking the square root is therefore 8y/x.

User Eddym
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories