Final answer:
The value of h(-2) is -13 for the function h(t)=4t-5. The substitution method is used, not the quadratic formula, as the function is not in quadratic form.
Step-by-step explanation:
The question requires us to find h(−2), where the function h(t) is defined as h(t)=4t−5. To find h(−2), we substitute t with −2 in the equation:
h(−2) = 4(−2) − 5 = −8 − 5 = −13
Therefore, the value of h(−2) is −13.
To clarify the student's additional reference to quadratic equations, when solving such an equation in the form at² + bt + c = 0, the quadratic formula is used, which states: t = −b ± √(b² − 4ac) / (2a). However, this is not directly applicable in solving for h(−2) in the function provided.
To find the value of h(-2), we can substitute -2 into the function h(t) = 4t - 5.
h(-2) = 4(-2) - 5
h(-2) = -8 - 5
h(-2) = -13
Therefore, the value of h(-2) is -13.