Question

For the function f(x) = 4x^2 - 50x + 126, at what value of x does f(x) reach its minimum?

a) x = 25/2
b) x = -25/2
c) x = 25
d) x = -25

Answer 1

To find the value of x where the function f(x) = 4x^2 - 50x + 126 reaches its minimum, we can use the vertex formula for a quadratic function.

Step-by-step explanation:

To find the value of x where the function f(x) = 4x^2 - 50x + 126 reaches its minimum, we can use the vertex formula for a quadratic function.

The vertex formula gives us the x-coordinate of the vertex of the parabola represented by the quadratic function.

In this case, the formula is x = -b/2a, where a = 4, and b = -50.

Substituting these values into the formula, we get x = -(-50)/2(4) = 50/8 = 25/4.

Therefore, the value of x at which f(x) reaches its minimum is x = 25/4.