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What is the maximum size fuse that may be used to protect a 60 kVA, nonsupervised transformer having a 4,160 V primary and 5% impedance? A. 25 A B. 35 A C. 30 A D. 20 A

User Rksprst
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Final answer:

The question involves using transformer equations to calculate the number of turns in a multi-purpose transformer's secondary coil and the maximum output currents based on primary input specifications.

Step-by-step explanation:

The question deals with the calculation of secondary coil turns and maximum output currents for a multi-purpose transformer based on the transformer's primary input specifications. These calculations involve understanding how a transformer operates, which is guided by the principle of electromagnetic induction and is described mathematically by the transformer equations that relate voltages and number of turns in the primary and secondary coils, considering the transformer's efficiency and impedance.

To find the number of turns in the secondary used to produce the given output voltages, we use the formula Vs/Vp = Ns/Np, where Vs is the secondary voltage, Vp is the primary voltage, Ns is the number of secondary turns, and Np is the number of primary turns. For maximum output currents, we apply the power conservation principle IpVp = IsVs, with currents Is and Ip in secondary and primary respectively.

User Rubia Gardini
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