Question

Consider an escalator at an angle of 45 degrees above the horizontal that moves with a velocity of 3 what is the vertical component of the escalator velocity

a) 3
b) 3 cos(45°)
c) 3 sin(45°)
d) 3 tan(45°)

Answer 1

The vertical component of the escalator velocity is approximately 2.121.

Step-by-step explanation:

The vertical component of the escalator velocity can be calculated using trigonometry. The angle of the escalator above the horizontal is 45 degrees. The velocity of the escalator is given as 3.

To find the vertical component of the velocity, we can use the sine function. The sine of 45 degrees is equal to the ratio of the vertical component to the hypotenuse.

So, the vertical component of the escalator velocity is given by:

Vertical component = Velocity * sin(45 degrees)

Substituting the given values, we have:

Vertical component = 3 * sin(45 degrees)

Using the value of sin(45 degrees) as 0.707, we can calculate:

Vertical component = 3 * 0.707 = 2.121

Therefore, the vertical component of the escalator velocity is approximately 2.121.