Question

A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0065 m/s² less than that at sea level (g_sea level = 9.83 m/s²). What is the observed free-fall acceleration at the mountain observatory?

a) 9.8235 m/s²
b) 9.8365 m/s²
c) 9.823 m/s²
d) 9.8265 m/s²

Answer 1

The observed free-fall acceleration at the mountain observatory is 9.8235 m/s², which is found by subtracting 0.0065 m/s² from the sea level acceleration of 9.83 m/s².

Step-by-step explanation:

The free-fall acceleration observed at the mountain observatory is found by subtracting 0.0065 m/s² from the acceleration due to gravity at sea level. Given g_sea level = 9.83 m/s², the calculation is as follows:

g_mountain = g_sea_level - 0.0065 m/s²

g_mountain = 9.83 m/s² - 0.0065 m/s²

g_mountain = 9.8235 m/s²

Therefore, the correct answer is a) 9.8235 m/s².