Question

Sodium chloride can be prepared by the reaction of sodium metal and chlorine gas. If 6.70 moles Na react with 3.20 moles Cl₂, how many moles NaCl are produced?

a) 9.90
b) 5.50
c) 3.35
d) 6.70

Answer 1

To calculate the number of moles of NaCl produced, we can use the stoichiometry of the reaction. The balanced chemical equation for the reaction of sodium with chlorine gas is:

2Na + Cl2 → 2NaCl

Therefore, the correct answer is:

a) 9.90

Step-by-step explanation:

To calculate the number of moles of NaCl produced, we can use the stoichiometry of the reaction. The balanced chemical equation for the reaction of sodium with chlorine gas is:

2Na + Cl2 → 2NaCl

Given that 6.70 moles of Na react with 3.20 moles of Cl2, we can use the stoichiometry of the reaction to determine the number of moles of NaCl produced. Since 2 moles of Na react with 1 mole of Cl2, we can set up the following equation:

2 * (6.70 moles) = 3.20 moles * 2

Solving for the number of moles of NaCl produced, we get:

3.20 moles * 2 = 6.70 moles

Therefore, the correct answer is:

a) 9.90