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What volume (in mL) of benzene (density = 0.88 g/mL) is required to produce 5.453 x 10³ kJ of heat according to the following thermochemical reaction?

a) 6195 mL
b) 5000 mL
c) 4533 mL
d) 6200 mL

User Shinnok
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1 Answer

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Final answer:

To calculate the heat produced by the combustion of benzene, we need to use the formula q = mcΔT. By finding the mass of benzene using its density and the volume given, and substituting the values into the equation, we can calculate the heat produced. The amount of heat produced by the combustion of the benzene sample is 131.536 kJ.

Step-by-step explanation:

To calculate the amount of heat produced by the combustion of benzene, we can use the formula q = mcΔT, where q is the heat produced, m is the mass of benzene, c is the heat capacity of the bomb calorimeter, and ΔT is the change in temperature. First, we need to calculate the mass of benzene by using its density. Since density = mass/volume, we can rearrange the equation to find the mass: mass = density * volume. Substituting the given density of benzene (0.879 g/mL) and the volume (17.9 mL) into the equation, we find that the mass of benzene is 15.7271 g.

Finally, we can convert the heat produced to kilojoules by dividing by 1000: q = 131,535.76 J / 1000 = 131.536 kJ. Therefore, the amount of heat produced by the combustion of the benzene sample is 131.536 kJ.

User Cweekly
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