Final answer:
After mixing equal volumes of 0.0700 M NH₃ and 0.0350 M HCl, the remaining concentration of NH₃ is 0.0350 M (as half of it has reacted), and the concentration of NH₄⁺ formed is also 0.0350 M. Option C is correct.
Step-by-step explanation:
When equal volumes of 0.0700 M NH₃ and 0.0350 M HCl are mixed, a neutralization reaction occurs where NH₃ acts as a base and HCl as an acid:
NH₃ (aq) + HCl (aq) → NH₄⁺ (aq) + Cl⁻ (aq)
Since HCl is the limiting reactant, it will completely react with NH₃. For every mole of HCl, there is one mole of NH₃ that reacts to form NH₄⁺. Initially, there is twice as much NH₃ as there is HCl. After the reaction, the amount of NH₃ that has not reacted will be:
Concentration of NH₃ before reaction - Concentration of HCl = 0.0700 M - 0.0350 M = 0.0350 M NH₃ left
The concentration of NH₄⁺ formed is equal to the original concentration of HCl, which is 0.0350 M since the reaction is 1:1. Therefore, the remaining concentration of NH₃ is 0.0350 M and the concentration of NH₄⁺ is also 0.0350 M. The correct answer is:
c) [NH₃] = 0.0700 M, [NH₄] = 0.0350 M