Question

An aqueous solution containing 9.74 g of lead(II) nitrate is added to an aqueous solution containing 6.15 g of potassium chloride. What is the resulting chemical reaction product?

a. Pb(NO₃)₂
b. KCl
c. PbCl₂
d. KNO₃

Answer 1

The resulting chemical reaction product of the mixture of lead(II) nitrate and potassium chloride is Lead(II) chloride (PbCl₂).

Step-by-step explanation:

The resulting chemical reaction product of the mixture of lead(II) nitrate and potassium chloride is Lead(II) chloride (PbCl₂). This is because a double displacement reaction occurs, where the lead ion (Pb²⁺) from lead(II) nitrate combines with chloride ion (Cl⁻) from potassium chloride to form an insoluble precipitate, lead(II) chloride. The remaining two products of the reaction are potassium nitrate (KNO₃) and sodium nitrate (NaNO₃), both of which remain in the aqueous state.