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Square root of 110 between 2 positive consecutive integers.

A. 10
B. 11
C. 12
D. 13

1 Answer

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Final answer:

The square root of 110 falls between the consecutive integers 10 and 11, so the correct answer is A. 10.

Step-by-step explanation:

The question is asking to identify which two consecutive positive integers the square root of 110 falls between. We know that 10² = 100 and 11² = 121. Since 110 is between 100 and 121, the square root of 110 must be between 10 and 11. Therefore, the correct answer is A. 10, because 11 would not be a consecutive integer after 10, and the square root of 110 is less than 11.

The square root of 110 falls between two positive consecutive integers. Let's find these integers by squaring consecutive integers until we find one that is greater than 110. We know that 10 squared (10^2) is 100 and 11 squared (11^2) is 121. Therefore, the square root of 110 falls between 10 and 11. So, the answer is B. 11.

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