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Calculate the address of the array location ar[4,3] in a two-dimensional array ar [1....5,1.....4] stored in row-major order in the main memory. Assume the base address is 1000, and each element in the array requires 4 bytes of storage.

(a) 1016
(b) 1024
(c) 1032
(d) 1040

User Utechtzs
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1 Answer

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Final answer:

The address of the element ar[4,3] in a row-major ordered array with base address 1000 and element size 4 bytes is 1056. It is important to count the total number of elements preceding the target element, considering complete rows and columns. The listed options do not include the correct answer.

Step-by-step explanation:

To calculate the memory address of the element ar[4,3] in a two-dimensional array stored in row-major order, we use the row-major address calculation formula. Given that the base address is 1000 and each element occupies 4 bytes, the address for ar[4,3] can be found by calculating the number of elements that precede it in memory and multiplying that count by the size of each element, then adding this product to the base address.

The array has 5 rows and 4 columns, and the element ar[4,3] is in the 4th row and 3rd column. To find the address, we consider the complete rows before the 4th row, which are 3 rows (since the array starts at 1), and 3 full columns in the 4th row before the 3rd element.

Calculating the position: (Number of full rows before 4th row * Number of elements per row) + Number of elements before the 3rd element in the 4th row = (3 * 4) + 2 = 14. Finally, the address for ar[4,3] is the base address + (14 * size of each element in bytes) = 1000 + (14 * 4) = 1056. Thus, the correct answer is not in the listed options.

User MagnusEffect
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