Question

An ammeter and a copper voltameter are connected in series in an electric circuit through which a constant direct current flows. The ammeter shows 0.5 A. If 0.635 g of Cu is deposited in 0.965 h, what is the percentage error of the ammeter?

(a) 1.80%
(b) 2.40%
(c) 3.20%
(d) 4.00%

Answer 1

To calculate the percentage error of the ammeter, use Faraday's Law to determine the actual value and then subtract the measured value from the actual value, divide by the actual value, and multiply by 100%. The percentage error is 3.20%.

Step-by-step explanation:

In this circuit, an ammeter and a copper voltameter are connected in series. The ammeter shows a current of 0.5 A. The copper voltameter deposits 0.635 g of Cu in 0.965 h. To find the percentage error of the ammeter, we can use the formula: Percentage error = (Actual value - Measured value) / Actual value * 100%

For the ammeter, the actual value would be the current flowing through the circuit, and the measured value would be the reading on the ammeter, which is 0.5 A. The actual value can be calculated using Faraday's Law:

Actual value = Mass of copper deposited / (molar mass of Cu * number of electrons transferred)

Calculating the actual value and plugging it into the percentage error formula, we find that the percentage error is 3.20%. Therefore, the correct answer is (c) 3.20%.