Question

X represents a nonmetal atom with an atomic mass of 122.28 amu. Calculate the number of grams of Ag2X in 0.4818 mol of Ag2X.

a) 22.13 g
b) 31.45 g
c) 42.89 g
d) 15.72 g

Answer 1

There are 162.89 g grams of Ag2X in 0.4818 mol of Ag2X. None of the given options is answer.

Step-by-step explanation:

1. Calculate the molar mass of Ag2X:

Atomic mass of Ag (silver): 107.87 amu

Atomic mass of X: 122.28 amu (given)

Molar mass of Ag2X = (2 × 107.87) + 122.28 = 338 amu/mol

2. Convert moles to grams:

Moles of Ag2X = 0.4818 mol

Mass of Ag2X = moles × molar mass

Mass of Ag2X = 0.4818 mol × 338 g/mol

Mass of Ag2X = 162.89 g

Therefore, there are 162.89 grams of Ag2X in 0.4818 mol of Ag2X.

None of the given options is answer.