153k views
0 votes
Let U be a random variable uniformly distributed on

(0,1). Determine the probability density function of Y=1−U.

a) f(y)=1
b) f(y)=0.5
c) f(y)=2
d) f(y)=1−y

User Apdastous
by
8.1k points

1 Answer

1 vote

Final answer:

To determine the pdf of Y=1−U, where U is uniformly distributed on (0,1), we find the derivative of the cdf of Y.

Step-by-step explanation:

In this case, we have Y = 1 - U, where U is a random variable uniformly distributed on the interval (0,1). To determine the probability density function (pdf) of Y, we need to find the derivative of the cumulative distribution function (cdf) of Y.

Since Y = 1 - U, the cdf of Y is given by F(y) = P(Y ≤ y) = P(1 - U ≤ y) = P(U ≥ 1-y) = 1 - P(U < 1-y) = 1 - (1-y), for 0 ≤ y ≤ 1.

Taking the derivative of the cdf, we get the pdf of Y as f(y) = dF(y)/dy = d(1 - (1-y))/dy = 1, for 0 ≤ y ≤ 1.

User Rzaaeeff
by
8.1k points