Question

HELP! In rectangle DEBC, Eb = 12 and Cb =4. What is the approximate distance from point E to point C? (I’m giving away robux to who ever helps me)

Answer 1

12.65

Step-by-step explanation:

By using pythagoras theorem :

(CE)^2 = (EB)^2 + (CB)^2

= (12)^2 + (4)^2

= 144+16

CE = (Root sign)160

= Approx. 12.64 rounded off to 12.65

Answer 2

The approximate distance from point E to point C is 12.65. The correct answer is: D

To find the distance from point E to point C in rectangle DEBC, we can use the Pythagorean Theorem since DEBC is a rectangle, and therefore DE and BC are perpendicular.

DE and BC are the legs of the right-angled triangle, and EC is the hypotenuse.

EC² = DE² + BC²

EB = 12 and BC = 4

EC² = 12² + 4²

EC² = 144 + 16

EC² = 160.

EC = √160 ≈ 12.65.

Therefore, the approximate distance from point E to point C is 12.65. Therefore, the correct answer is: (D) 12.65.