Final answer:
The work and energy change when 67.11 g of Cu₂O is oxidized at a constant pressure of 1.00 bar can be determined using the equation w = -PAV. Since the volume increases as the reaction proceeds, the work done by the system is negative, indicating that the system loses energy by performing work on its surroundings.
Step-by-step explanation:
The work and energy change when 67.11 g of Cu₂O is oxidized at a constant pressure of 1.00 bar can be determined using the equation
where w is the work done by the system, P is the external pressure, A is the change in volume, and V is the volume change.
In this case, since the volume increases as the reaction proceeds, the work done by the system is negative, indicating that the system loses energy by performing work on its surroundings. The energy change is also negative.