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Please help!!!!!!!!!

Please help!!!!!!!!!-example-1
User Aly
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1 Answer

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The graph of the function y = 4/3 x - 6 is attached

m = slope = 4/3

c = y-intercept = -6

The two points plotted are (3, -2) and (6, 2)

How to find the points

From the equation, y = 4/3 x - 6. We liken it to the general equal of slope intercept

y = mx + c

Where

m = slope = 4/3

c = y-intercept = -6

To find two points, on the line, we substitute the input value and solve for the output

x = 3, y = 4/3 (3) - 6 = -2, (3, -2)

x = 6, y = 4/3 (6) - 6 = 2, (6, 2)

Please help!!!!!!!!!-example-1
User Artyom Neustroev
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8.4k points