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The pitch and the number of divisions on the circular scale for a given screw gauge are 0.5 mm and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 mm and 48, respectively. The thickness of this sheet is:_____

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Final answer:

The thickness of the thin sheet is 22.5 mm.

Step-by-step explanation:

To find the thickness of the thin sheet using the given readings of the main scale and the circular scale, we need to first understand how the screw gauge works.

The pitch of the screw gauge is the distance traveled by the screw per revolution. In this case, the pitch is 0.5 mm. The circular scale has 100 divisions.

When the screw gauge is fully tightened without any object, the zero of the circular scale lies 3 divisions below the mean line. This means that the initial reference point is 3 divisions below the mean line.

Now, let's calculate the thickness of the thin sheet:

Step 1: Subtract the initial reference point (3 divisions) from the circular scale reading for the thin sheet (48 divisions): 48 - 3 = 45 divisions.

Step 2: Multiply the number of divisions (45) by the pitch (0.5 mm/division): 45 * 0.5 mm/division = 22.5 mm.

Therefore, the thickness of the thin sheet is 22.5 mm.

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