Final answer:
The maximum file size in the file system described is 134,349,312 bytes, which is approximately 128.4 MBytes when considering the direct, indirect, and doubly indirect block addresses in conjunction with the size of each disk block and disk block address.
Step-by-step explanation:
To calculate the maximum possible file size in the given file system with 4 direct block addresses, 1 indirect block address, and 1 doubly indirect block address, we have to consider the size of each disk block and address. Here's the breakdown:
- Direct blocks: 4 blocks × 128 bytes/block = 512 bytes
- Indirect block: (128 bytes/block address) × (128 bytes/block) / 16 bytes/block address = 1,024 blocks × 128 bytes/block = 131,072 bytes
- Doubly indirect block: (128 bytes/block address) × (128 bytes/block address) / 16 bytes/block address × 128 bytes/block = 1,024 blocks × 131,072 bytes = 134,217,728 bytes
The maximum file size is the sum of the above:
Maximum file size = Direct blocks + Indirect blocks + Doubly indirect blocks = 512 bytes + 131,072 bytes + 134,217,728 bytes = 134,349,312 bytes.
In terms of larger units, this is approximately 128.4 MBytes (1 MByte = 1,024 KBytes).