Final answer:
The magnetic force on a current-carrying loop in a magnetic field is given by F = I×℧ × B. For a perpendicular current and magnetic field, the force direction can be found using RHR-1, and the force per unit length is I℧B. For a 20.0-cm-wide loop with a 5.00 A current, the force per tesla would be calculated with this formula. Therefore, the correct answer is option A) Magnetic field strength
Step-by-step explanation:
The magnetic force acting on a current-carrying wire in a magnetic field is described by the equation F = I×℧ × B, where I is the current in the wire, ℧ is the length vector of the wire, and B is the magnetic field.
When the current and the magnetic field are perpendicular, as in this case, the angle between them is 90 degrees, which simplifies the equation since sin(90°) = 1. This means we can calculate the force per unit length by rearranging the equation to include ℧ on the left-hand side.
According to the right-hand rule-1 (RHR-1), the direction of the magnetic force can be determined by orienting the thumb of the right hand in the direction of the current and the fingers in the direction of the magnetic field; the force direction is then out of the palm. For a rectangular loop of wire in a uniform magnetic field, the magnetic force on the left section of the loop can be found by applying this rule to that segment.
The directionality of the magnetic force is given clearly after taking the cross product in unit vector notation. In the case of a rectangular loop, the net force on the loop might be zero, but there could be a net torque, calculated by τ = μ × B, with μ representing the magnetic dipole moment of the loop.
For the question about the force per tesla on a 20.0-cm-wide loop with a 5.00 A current, the force per unit length is I℧B, which simplifies to 5.00 A × 0.20 m × 1 T for a force per tesla calculation.
Therefore, the correct answer is option A) Magnetic field strength