229k views
2 votes
What is the length of the line in the first quadrant of an x−y coordinate plane? A line segment extends from (2,7) to (4,2).

a.√'20
b. √'29
c. 5
d. √'13

User Vikbert
by
7.0k points

1 Answer

2 votes

Final answer:

The length of the line segment between the points (2,7) and (4,2) is the square root of 29, denoted as √29. Therefore, the length of the line segment is √'29, which is option b.

Step-by-step explanation:

The question asks us to calculate the length of a line segment in an x-y coordinate plane between the points (2,7) and (4,2). To find this length, we can use the distance formula, which is derived from the Pythagorean theorem:

d = √((x2 - x1)² + (y2 - y1)²)

Substituting the given points into the distance formula:

d = √((4 - 2)² + (2 - 7)²)
d = √((2)² + (-5)²)
d = √(4 + 25)
d = √29

Therefore, the length of the line segment is √29.

The length of a line segment in an x-y coordinate plane can be found using the distance formula. The formula is:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case, the coordinates of the points are (2,7) and (4,2). Plugging these values into the formula, we get:

d = sqrt((4 - 2)^2 + (2 - 7)^2) = sqrt(2^2 + (-5)^2) = sqrt(4 + 25) = sqrt(29).

Therefore, the length of the line segment is √'29, which is option b.

User Paul Sachs
by
7.5k points