Final answer:
When 8.964 mol of hydrazine (assuming dinitrogen tetrahydride is meant to be hydrazine) decomposes, it forms 17.928 moles of ammonia, which is not listed in the answer choices. This indicates a possible typo in the provided options or the original question.
Step-by-step explanation:
The question involves the decomposition of dinitrogen tetrahydride, which we can represent in a balanced chemical equation to understand the stoichiometry of the reaction. Unfortunately, the given chemical name dinitrogen tetrahydride does not correspond to a well-known compound, and appears to be a misconception, possibly meaning hydrazine (N2H4). Assuming we deal with hydrazine decomposing into ammonia (NH3) and nitrogen gas (N2), the correct balanced equation would be:
N
2
H
4
(l) → 2 NH
3
(g) + N
2
(g)
According to this equation, two moles of ammonia are formed for every mole of hydrazine that decomposes. To find the number of moles of ammonia produced from an 8.964 mol sample of hydrazine:
- Multiply the moles of hydrazine by the ratio of moles of ammonia to moles of hydrazine from the balanced equation, which is 2 moles of NH3 for every 1 mole of N2H4.
- The calculation is: 8.964 mol N2H4 × (2 mol NH3 / 1 mol N2H4) = 17.928 moles of NH3.
Therefore, the answer is none of the options provided as 17.928 mol is the correct amount of ammonia produced, suggesting that there could be a typo in the problem statement or the provided options.