Final answer:
The amount of ZnCl₂ produced from the reaction can be determined using stoichiometry. The moles of Zn and HCl are calculated, and since 1 mole of Zn produces 1 mole of ZnCl₂, the moles of ZnCl₂ produced will be equal to the moles of Zn. Therefore, the amount of ZnCl₂ produced is 0.038 mol.
Step-by-step explanation:
To determine the amount of ZnCl₂ produced from the reaction, we need to use stoichiometry. First, calculate the moles of Zn and HCl:
Moles of Zn = mass of Zn / molar mass of Zn = 2.5 g / 65.38 g/mol = 0.038 mol
Moles of HCl = mass of HCl / molar mass of HCl = 5.0 g / 36.46 g/mol = 0.137 mol
According to the balanced equation Zn + 2HCl → ZnCl₂ + H₂, the ratio between Zn and ZnCl₂ is 1:1. This means that for every 1 mole of Zn, 1 mole of ZnCl₂ is produced.
Therefore, the moles of ZnCl₂ produced will be equal to the moles of Zn.
So, the amount of ZnCl₂ produced is 0.038 mol.