Final answer:
In projectile motion, the highest point of the trajectory is known as the maximum height. In this case, the projectile is fired at a 30° angle above the horizontal from a starting height of 20 m.
Step-by-step explanation:
In projectile motion, the highest point of the trajectory is known as the maximum height. To determine the maximum height, we need to consider the vertical motion of the projectile. In this case, the projectile is fired at a 30° angle above the horizontal from a starting height of 20 m.
Using the equations of motion, we can calculate the maximum height reached by the projectile. The initial vertical velocity can be found by multiplying the initial velocity of the projectile by the sine of the launch angle. The time taken to reach the maximum height can be calculated using the equation t = (2 * v_vertical) / g, where v_vertical is the initial vertical velocity and g is the acceleration due to gravity.
Once the time is determined, we can use the equation h_max = h_0 + v_vertical * t - (0.5 * g * t^2), where h_max is the maximum height, h_0 is the starting height, v_vertical is the initial vertical velocity, t is the time, and g is the acceleration due to gravity.
Substituting the values in the equation, we get:
h_max = 20 + (50 * sin(30°) * (2 * (50 * sin(30°)) / 9.8) - (0.5 * 9.8 * ((2 * (50 * sin(30°)) / 9.8))^2)
Simplifying the equation will give us the maximum height reached by the projectile.