Question

For the chemical reaction occurring when NaF (tube #8, sodium oxalate) is added to disturb the following equilibrium.

Fe3+ (aq) + SCN- (aq) → FeSCN2+ (aq)

How to get started? Find the experiment in Part A video at (video: 9:33 min) and gather the provided information precipitate or complex ion formation

1. Next, find the information on the addition of NaF to the equilibrium in the "Procedure" section of Part A, "Experiment" tab of the description page. Look for the formula of the precipitate, the state is "(s)," or complex, the state is "(aq)," formed when NaF was added.

2. Next, combining information from 1 and 2 you will find out the formula and the state of the product: this will be the ONLY product. 3. Finally, the reactants will be the list of ions in the product.

Example: if you find out that the reaction gives rise to AD(s) product, then

start with: reactant(s) →AD(s)

the reactants are A ion and D ion (these are the composing ions of AD);

thus, the net ionic equation is: A+(aq) + D¯(aq) →AD(s)

Answer 1

The chemical reaction occurring when NaF is added to disturb the equilibrium of Fe3+(aq) + SCN-(aq) → FeSCN2+(aq) is Fe3+(aq) + SCN-(aq) + NaF(aq) → Fe(SCN)2+(aq) + Na+(aq) + 2F-(aq).

Step-by-step explanation:

To determine the chemical reaction occurring when NaF is added to disturb the equilibrium of Fe3+(aq) + SCN-(aq) → FeSCN2+(aq), you need to gather information from the provided references. In Figure 16.8.1b, it is shown that the addition of thiocyanate ion (SCN-) results in the formation of the red Fe(SCN)2+ ion. In Equation 9.5.7, the net ionic equation is given as 2 Ag+ (aq) + Cr2O7-(aq) → Ag2Cr2O7(s). Therefore, the equation for the reaction when NaF is added to the equilibrium is:

Fe3+(aq) + SCN-(aq) + NaF(aq) → Fe(SCN)2+(aq) + Na+(aq) + 2F-(aq)