Question

ISP have been allocated the address block 200.23.16.0/21. ISP, wants to divide its address block into four equal-sized address blocks and give one to each of four organizations. Write the address range and also subnet mask for each organization.

Instructions for answering this question:

1. Write the address range for every organization in decimal number format. Refer the following sample answer response if unsure:

200.23.16.0 - 200.23.16.255/21 [[initial address block]- [final address]/[size of prefix in bits]]

• 2. The first four blanks are for the address ranges of each of the four organizations and the last blank is provided to add the subnet mask. (Numbers and dots only. eg. 255.255.255.255)

Answer 1

The ISP can divide its address block into four equal-sized address blocks using subnetting. Each organization will be allocated one of these blocks with a specific address range and subnet mask.

Step-by-step explanation:

The ISP has been allocated the address block 200.23.16.0/21. In order to divide this address block into four equal-sized address blocks, the ISP can use subnetting. Each organization will be allocated one of these four address blocks. To determine the address range for each organization, we need to divide the available IP addresses equally among the four blocks. Each block will have 512 IP addresses (2^9).

The address range and subnet mask for each organization will be:

1. Organization 1: Address Range: 200.23.16.0 - 200.23.16.127, Subnet Mask: 255.255.255.128
2. Organization 2: Address Range: 200.23.16.128 - 200.23.16.255, Subnet Mask: 255.255.255.128
3. Organization 3: Address Range: 200.23.17.0 - 200.23.17.127, Subnet Mask: 255.255.255.128
4. Organization 4: Address Range: 200.23.17.128 - 200.23.17.255, Subnet Mask: 255.255.255.128