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What Is The Enthalpy Change When 37.1 ML Of 0.500 M Sulfuric Acid Reacts With 15.9 ML Of 0.101 M Potassium Hydroxide?

User Fadelakin
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Final answer:

The calculation of enthalpy change requires specific enthalpy data for the given reaction, which is not provided in the information available. The steps would include finding moles from molarity and volume and then using the molar enthalpy of reaction.

Step-by-step explanation:

To find the enthalpy change when 37.1 mL of 0.500 M sulfuric acid reacts with 15.9 mL of 0.101 M potassium hydroxide, we must first convert the volumes of solutions to moles.

Since we do not have a specific enthalpy change value for the given reaction between sulfuric acid and potassium hydroxide, we cannot calculate an exact enthalpy change for this with the provided information.

Typically, one would use the molarity and volume of the reactants to find the number of moles, determine the limiting reactant, and then use the molar enthalpy change to calculate the total enthalpy change for the reaction.

User Sinaza
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