Final answer:
To solve the given system of equations, we can use the method of substitution. After rearranging the second equation and substituting the value of t into the first equation, we end up with a quadratic equation. Solving this quadratic equation gives us the solutions t = 18, u = 3 and t = -45, u = -4.
Step-by-step explanation:
The given equations are:
To solve this system of equations, we can use the method of substitution. We can rearrange the second equation to solve for t as t = 9u - 9. Then substitute this value of t into the first equation:
(9u - 9)u = 99
Expanding and rearranging the equation, we get:
9u^2 - 9u - 99 = 0
Factoring out a 9, we have:
9(u^2 - u - 11) = 0
Solving for u using the quadratic formula gives two solutions: u = 3 and u = -4. Substitute these values back into the equation t = 9u - 9 to find the corresponding values of t: t = 18 and t = -45.
Therefore, the solutions to the system of equations are t = 18, u = 3 and t = -45, u = -4.