Question

A constant applied force of pushes a box with a mass a distance across a level floor. The coefficient of kinetic friction between the box and the floor is μ = 0.110. Calculate the force.

Answer 1

The force applied to overcome kinetic friction and move the box is

Fapplied = μ⋅m⋅g, where μ=0.110, m is the mass of the box, and g is the acceleration due to gravity.

Step-by-step explanation:

To calculate the force applied to overcome kinetic friction and move the box, we can use the following equation:

Fapplied = Ffriction

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The frictional force Ffriction can be determined using the equation:

Ffriction = μ⋅N

where:

μ is the coefficient of kinetic friction (0.110 in this case),

N is the normal force exerted by the floor on the box.

Assuming the box is on a level floor and there is no vertical acceleration (i.e., it's not lifting off the floor), the normal force N is equal to the weight of the box (mg), where m is the mass of the box and g is the acceleration due to gravity (g≈9.8m/s2 ).

Therefore, the force applied to overcome friction is given by:

Fapplied = μ⋅m⋅g

Now, you can substitute the values for μ, m, and g into the equation to find the force applied.