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A second 0.69 kg bullfrog is on a log tilted 40° above horizontal. How large is the normal force of the log on this bullfrog?

User Jeff Wu
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Final answer:

The normal force on a bullfrog on an angled log can be calculated using the mass of the bullfrog, the acceleration due to gravity, and the cosine of the angle of the log with the horizontal. The equation used is N = mg cos(θ).

Step-by-step explanation:

The student is asking about the magnitude of the normal force acting on a bullfrog sitting on a titled log. To find the normal force, we need to consider the component of the gravitational force perpendicular to the surface of the log. The bullfrog has a mass of 0.69 kg and the log is tilted at a 40° angle above the horizontal.

To calculate the normal force (N), we use the equation N = mg cos(θ), where m is the mass of the bullfrog, g is the acceleration due to gravity (9.80 m/s²), and θ is the angle of the log with respect to the horizontal. Plugging the values into the equation: N = 0.69 kg × 9.80 m/s² × cos(40°).

After calculating, you would find the normal force exerted by the log on the bullfrog, which would be less than the bullfrog's weight due to the angle of the log.

User NEBEZ
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