Final answer:
The 76th term of the arithmetic sequence 16, 14, 12, ... is calculated using the formula for the nth term of an arithmetic sequence. The first term is 16, and the common difference is -2. Using these values, the 76th term is found to be -134.
Step-by-step explanation:
To find the 76th term of the arithmetic sequence 16, 14, 12,..., we need to use the formula for the nth term of an arithmetic sequence, which is an = a1 + (n - 1)d, where a1 is the first term, d is the common difference, and n is the term number.
In this sequence, a1 = 16 and the common difference d can be calculated as 14 - 16 = -2. Now, let's find the 76th term (a76):
a76 = 16 + (76 - 1)(-2) = 16 - 150 = -134
Therefore, the 76th term of the sequence is -134, which corresponds to option D.
What is an arithmetic sequence? An arithmetic sequence is an ordered set of numbers that have a common difference between each consecutive term. For example in the arithmetic sequence 3, 9, 15, 21, 27, the common difference is 6. An arithmetic sequence can be known as an arithmetic progression.
An arithmetic sequence is a sequence where each term increases by adding/subtracting some constant k. This is in contrast to a geometric sequence where each term increases by dividing/multiplying some constant k.