Final answer:
To distribute 91 strawberries into bowls that can hold 11 each, divide the total number of strawberries by the number per bowl, resulting in 8 bowls needed, with the last bowl having 3 strawberries left over.
Step-by-step explanation:
To determine the number of bowls needed for the strawberries, simply divide the total number of strawberries by the number of strawberries that each bowl should contain.
You would need a total of 8 bowls to evenly distribute 91 strawberries, with 11 in each bowl, plus one bowl for the remaining 3 strawberries.
Start by taking the total number of strawberries, which is 91, and dividing that number by the number of strawberries per bowl, which is 11. This gives you:
91 ÷ 11 = 8 bowls with 3 strawberries left over. Since you cannot have a fraction of a bowl, you round up to the nearest whole number to ensure that all strawberries are accounted for.
Therefore, we need 8 bowls in total to hold all the strawberries but remember that the last bowl will not be completely full; it will only have 3 strawberries. This kind of division problem is common in mathematics and is a practical example of how division can be applied to solve problems involving the distribution of items into groups of a specific size.