Final answer:
The complete ionic equation for the reaction between lead perchlorate and sodium sulfide is: Pb2+ (aq) + 2 ClO4− (aq) + 2 Na+ (aq) + S2− (aq) → PbS (s) + 2 Na+ (aq) + 2 ClO4− (aq), with the correct answer being option A.
Step-by-step explanation:
The student asked to write the complete ionic equation for the reaction between lead perchlorate and sodium sulfide. The correct answer among the given options is A.
Here is the balanced chemical equation for the reaction:
Pb(ClO4)2 (aq) + Na2S (aq) → PbS (s) + 2 NaClO4 (aq)
To write the complete ionic equation, we need to separate the soluble ionic compounds into their constituent ions:
Pb2+ (aq) + 2 ClO4− (aq) + 2 Na+ (aq) + S2− (aq) → PbS (s) + 2 Na+ (aq) + 2 ClO4− (aq)
Note that the sodium (Na+) and perchlorate (ClO4−) ions are spectators and don't participate in the substantive change, and thus also appear on both sides of the equation.