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write a general formula to describe the variation: m varies jointly with the inverse of the square of b and directly with the cube of b.

User Imapler
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1 Answer

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Final answer:

The general formula for the variation where m varies jointly with the inverse of the square of b and directly with the cube of b can be expressed as m = k · b^{3} · ⅓b^{2}, which simplifies to m = k · b.

Step-by-step explanation:

The student is asking for a general formula that describes a relationship where m varies jointly with the inverse of the square of b and directly with the cube of b.

A joint variation means that m is directly proportional to more than one variable. In this case, m is directly proportional to the cube of b, and inversely proportional to the square of b. Combining these relationships, we get the following formula:

m = k · ⅓b^{3} where ⅓ means the inverse and k is the constant of proportionality.

To clarify, the cube of b is b raised to the power of 3, denoted as b^{3}, and the inverse of the square of b is 1 divided by the square of b, denoted as b^{-2} or ⅓b^{2}. Hence, the complete general formula considering both direct and inverse variations will be:

m = k · b^{3} · ⅓b^{2}

Since ⅓b^{2} is equivalent to b^{-2}, you can also write this as:

m = k · b^{1}

User HarshitMadhav
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