Final answer:
To calculate the number of photoelectrons ejected per second from a given area of sodium metal, you need to find the energy of one photon, calculate the number of photons incident on the area per second, and then calculate the number of photoelectrons per second. In this case, the answer is 1.18 x 10^17 photoelectrons per second.
Step-by-step explanation:
To calculate the number of photoelectrons per second ejected from a 1.00-mm² area of sodium metal by 500-nm EM radiation having an intensity of 1.30 kW/m²:
Step 1: Find the energy of one photon using E = hc/λ, where h is Planck's constant (6.63 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the EM radiation in meters. Convert the energy to joules.
Step 2: Calculate the number of photons incident on the area per second using the equation I = P/A, where I is the intensity of the radiation in watts per square meter, P is the power of the radiation in watts, and A is the area in square meters.
Step 3: Find the number of photoelectrons per second using the equation n = NE, where n is the number of photoelectrons per second, N is the number of photons incident on the area per second, and E is the energy of one photon in joules.
The answer is: 1.18 x 10^17 photoelectrons per second