Final answer:
The solubility concentration of carbonate ions in a saturated solution of zinc carbonate at 25°C is equal to the molar solubility of zinc carbonate.
Step-by-step explanation:
The solubility product constant (Ksp) of zinc carbonate (ZnCO3) is given as 1.0 × 10–10 at 25°C. To find the solubility concentration of carbonate ions in a saturated solution, we can assume that the molar solubility of ZnCO3 is equal to the concentration of carbonate ions, since each molecule of ZnCO3 will yield one carbonate ion. Let's denote the molar solubility of ZnCO3 as 's'. Therefore, [CO3²-] = s. Since ZnCO3 dissociates to form one Zn²+ and one CO3²-, the equilibrium concentrations of Zn²+ and CO3²- will also be equal to 's'. Hence, [Zn²+] = [CO3²-] = s.
Therefore, the solubility concentration of carbonate ions in a saturated solution at 25°C is 's'.