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What is the molarity of an HCl solution if 24.0 mL is completely neutralized by 98.0 mL of 0.250 MCa(OH)₂?

User Esad
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Final answer:

The molarity of the HCl solution can be calculated using the formula M = moles of solute / volume of solution. By calculating the moles of Ca(OH)₂ that reacted with the HCl solution and then converting them to moles of HCl, we can determine the molarity of the HCl solution.

Step-by-step explanation:

To calculate the molarity of the HCl solution, we can use the equation:



Molarity (M) = moles of solute / volume of solution (in liters)



First, we need to calculate the moles of Ca(OH)₂ that reacted with the HCl solution:



Moles of Ca(OH)₂ = molarity of Ca(OH)₂ * volume of Ca(OH)₂



Now, since the reaction between HCl and Ca(OH)₂ is 1:2, the moles of HCl can be calculated by multiplying the moles of Ca(OH)₂ by 2:



Moles of HCl = 2 * moles of Ca(OH)₂



Finally, to find the molarity of the HCl solution, we divide the moles of HCl by the volume of HCl:



Molarity of HCl = moles of HCl / volume of HCl

User Giulio Centorame
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