Question

Jason works for a moving company. A 95 kg wooden crate is sitting on the wooden ramp of his truck; the ramp is angled at 11∘.What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving up the ramp?

Express your answer with the appropriate units.

Answer 1

To determine the magnitude of the force that Jason needs to exert on the crate to get it to start moving up the ramp, we need to use the concept of static friction. The force required to overcome static friction is given by the equation: F_s = μs * N, where μs is the coefficient of static friction and N is the normal force.

Step-by-step explanation:

To determine the magnitude of the force that Jason needs to exert on the crate to get it to start moving up the ramp, we need to use the concept of static friction. The force required to overcome static friction is given by the equation:

F_s = μs * N,

where μs is the coefficient of static friction and N is the normal force. Since the crate is on an inclined plane, the normal force is given by:

N = m * g * cos(θ),

where m is the mass of the crate, g is the acceleration due to gravity, and θ is the angle of the ramp.

Substituting the values given in the question, we can calculate the static frictional force:

F_s = μs * m * g * cos(θ).

Therefore, the magnitude of the force that Jason needs to exert on the crate to get it to start moving up the ramp is equal to the static frictional force, which can be calculated using the equation above.