Final answer:
To calculate the moles of anhydrous KAl(SO₄)₂, one must use the mass of the substance and its molar mass. The formula moles = mass / molar mass is applied. An example calculation is provided with hypothetical values.
Step-by-step explanation:
To calculate the number of moles of anhydrous KAl(SO₄)₂, we must use stoichiometry based on the balanced chemical equation for the relevant chemical reaction. Unfortunately, your provided information does not include a chemical reaction or more context, and the formula KAK(SO₄)₂ seems to have a typo. Assuming KAl(SO₄)₂ is the correct formula, we need the mass of the substance and its molar mass to calculate the moles.
Here’s a step-by-step example using a different compound, HNO3, as an analogous process:
- Calculate the molar mass of HNO3 (which would be similar to finding the molar mass of KAl(SO₄)₂).
- Use the mass of HNO3 to find moles using the formula: moles = mass / molar mass.
- Incorporate the stoichiometry if necessary to connect with other compounds in the reaction.
We also need the actual mass of the KAl(SO₄)₂ sample to be able to calculate the moles. If we had a mass of, for example, 10.0 grams of KAl(SO₄)₂ and its molar mass were 258.2 g/mol, then the moles of KAl(SO₄)₂ would be 10.0 g / 258.2 g/mol, which equals approximately 0.0387 moles.