Final answer:
To balance a seesaw with children of different weights, the force exerted on the side of the lighter-weight child must be higher than the weight of the heavier child, since the lighter child will be sitting farther from the pivot point to create equal torque and achieve equilibrium.Option C is the correct answer.
Step-by-step explanation:
If two children of different weights are on a seesaw, the force that needs to be exerted on the lighter-weight child's side to balance the seesaw is more than the weight of the heavier child. This is because the seesaw is a lever system that follows the principles of torque and equilibrium.
The lighter child must sit farther from the fulcrum (pivot) compared to the heavier child to create equal torque. This is because torque is the product of force and the distance from the pivot point, and the balance is achieved when the product of the weight and the distance from the fulcrum is equal for both sides of the seesaw.
For example, if the heavier child weighs more, they must sit closer to the fulcrum. Conversely, the lighter child sits farther from it. Thus, the force on the seesaw exerted by the lighter child, when considering the distance from the fulcrum, needs to be higher to create a balance.