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A 1400 kg car takes a 50-m-radius unbanked curve at 12 m/s. What is the radius r of the circle?

a) 30 m
b) 40 m
c) 50 m
d) 60 m

User Haidee
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1 Answer

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Final answer:

The minimum coefficient of friction needed for the car to negotiate the unbanked curve is approximately 0.29.

Step-by-step explanation:

The centripetal force required for a car to negotiate an unbanked curve can be calculated using the equation:

Fc = mv²/r

Where Fc is the centripetal force, m is the mass of the car, v is its velocity, and r is the radius of the curve. Rearranging the equation gives:

r = mv²/Fc

Plugging in the given values:

r = (1400 kg)(12 m/s)²/(Friction force)

Since the friction force is equal to the centripetal force, the equation becomes:

r = (1400 kg)(12 m/s)²/(μmg)

Where μ is the coefficient of friction and g is the acceleration due to gravity.

Given radius = 50m, m = 1400kg, v = 12 m/s, g ≈ 9.8 m/s², plugging in the values and solving for μ:

μ = (1400 kg)(12 m/s)²/[(50m)(9.8 m/s²)(1400 kg)]

μ ≈ 0.29

Therefore, the minimum coefficient of friction needed for the car to negotiate the unbanked curve is approximately 0.29.

User Gal Naor
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