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Is there a direction u in which the rate of change of the temperature function T(x,y,z) = 2xy-yz (temperature in degrees Celsius, distance in feet) at P(1,-1,1) is -3 deg C/ft? Give reasons for your answer.

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Final answer:

To find a direction u in which the rate of change of the temperature function T(x,y,z) at P(1,-1,1) is -3 deg C/ft, we need to find the gradient vector of T at that point. However, the given information is not sufficient to determine if there is a direction u that satisfies the given condition.

Step-by-step explanation:

To find a direction u in which the rate of change of the temperature function T(x,y,z) at P(1,-1,1) is -3 deg C/ft, we need to find the gradient vector of T at that point. The gradient vector represents the direction of the steepest increase of the temperature function. The rate of change in that direction is given by the dot product of the gradient vector and the unit vector u. So, we need to find the vector u that satisfies the equation ∇T · u = -3, where ∇T is the gradient vector of T.

To find ∇T, we need to calculate the partial derivatives of T with respect to x, y, and z, and evaluate them at P(1,-1,1). Once we have ∇T, we can solve the equation ∇T · u = -3 for u. If a solution exists, then u is the direction in which the rate of change of T is -3 deg C/ft at P(1,-1,1).

However, the given information is not sufficient to calculate ∇T and solve for u. We need to know the coordinates of the other points in the domain of T to determine the gradient vector. Without that information, we cannot determine if there is a direction u in which the rate of change of T at P(1,-1,1) is -3 deg C/ft.

User Mark Melgo
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