Question

When the quadratic function f is graphed in the xy-plane, where y=f(x), its vertex is (-2,5). What is the value of the coefficient of the x² term?

A) -2
B) 5
C) 0
D) -5

Answer 1

The coefficient of the x² term is 5.

Step-by-step explanation:

The quadratic function f(x) is of the form ax² + bx + c. The vertex form of a quadratic function is given by f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola. In this question, the vertex is (-2, 5), so the equation becomes f(x) = a(x + 2)² + 5.

To find the coefficient of the x² term, we need to determine the value of a. Since the parabola opens upward and the vertex is a minimum point, a must be positive. Therefore, the coefficient of the x² term is a positive value.

The answer is B) 5.