Question

Spencer has a bag of gumballs. The bag contains 6 red gumballs, 3 blue gumballs, and 7 green gumballs and 4 yellow gumballs. Spencer will randomly select one gumball from the bag, replace it, then select another gumball. What is the probability he will select a red gumball then a yellow gumball?

Answer 1

To find the probability of selecting a red gumball and then a yellow gumball from the bag, we need to calculate the probability of each event and multiply them together.

Step-by-step explanation:

To find the probability of selecting a red gumball and then a yellow gumball from the bag, we need to calculate the probability of each event and multiply them together.

The probability of selecting a red gumball on the first draw is 6 red gumballs out of a total of 6+3+7+4=20 gumballs.

The probability of selecting a yellow gumball on the second draw, after replacing the first gumball, is 4 yellow gumballs out of a total of 20 gumballs.

Therefore, the probability of selecting a red gumball and then a yellow gumball is (6/20) * (4/20) = 24/400 = 0.06 or 6%.